The Seattle Seahawks have officially signed 2020 sixth round pick, wide receiver Freddie Swain, to his rookie contract.
Swain becomes the second of Seattle’s eight-man draft class to sign his rookie deal, following tight end Colby Parkinson.
All rookie contracts are four-year deals and the amount tendered is based on where they were selected in the draft. For Swain, who was selected 214st overall, he will receive a four-year deal worth $3.42 million, which includes $129,412 in signing bonuses spread out over four years.
While these deals are predetermined, the signing does have an impact on the salary cap. Swain will be a $642,353 hit against the team’s cap space in 2020, a figure that will rise incrementally each year through the 2023 season, as long as he remains on the roster.
Of course, Swain has to prove he will even make the roster first, a tall order with Seattle’s crowded wide receiver room. Tyler Lockett and DK Metcalf are both locks to be the top two options for Russell Wilson, and Phillip Dorsett, David Moore and John Ursua are going to challenge for additional spots as well.
Add in a pair of undrafted free agents, Aaron Fuller and Seth Dawkins, and the possibility that Parkinson and/or fellow tight end Stephen Sullivan line up out wide this season, and Swain will have a lot of ground to cover if he wants to make the active roster in camp.
Even if he doesn’t, Swain will likely be a practice squad player, and he has the speed and special teams acumen to eventually be a playmaker for this Seattle offense.
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