Ohio State golfer Maxwell Moldovan qualifies for Barbasol Championship

In case you missed it, Maxwell Moldovan will be representing Ohio State in a PGA Tour event this weekend. #GoBucks

Ohio State men’s golfer, Maxwell Moldovan shot a -7 under to finish in second place at the PGA Tour’s Monday qualifier earlier this week to qualify for this weekend’s Barbasol Championship. With the result, he is one of just four in a field of 65 golfers to make the cut at Boone’s Trace National Golf Club.

It’ll be Moldovan’s first official PGA Tour event when he tees off at Champions Course at Keene Trace Golf Club in Nicholsville, Kentucky, though he did qualify for both of the last two U.S. Opens. He will be joining two other Buckeyes — Ryan Amour and Bo Hoag — this week in the field.

Moldovan continues to build upon a stellar career. He set a single-season Ohio State scoring record for the third consecutive year and finished in the top 20 in 11-of-13 events this season. He had a whopping seven top-five finishes.

Join us in wishing Moldovan a great showing on tour this weekend in Kentucky.

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