Myles Garrett wins AFC Defensive Player of the Week

Garrett captured the award for his 2-sack effort against the Cowboys

Congrats are in order for Browns defensive end Myles Garett. On Wednesday, Garrett was named the AFC’s Defensive Player of the Week for his efforts against the Dallas Cowboys on Sunday.

Garrett had two sacks of Cowboys QB Dak Prescott, including a strip-sack — the third week in a row Garrett forced a turnover with a sack. He also added a TFL in the run game and led all pass rushers with eight total QB pressures in Week 4.

Even in a game where the Cowboys rallied for 38 points, Garrett’s performance was strong enough to earn the prize as the best in the AFC in Week 4.

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