Lamar Jackson wins second straight AFC Offensive Player of the Week award

Lamar Jackson’s perfect passer rating and spectacular rushing won the Ravens quarterback his third weekly award of the 2019 season.

For his work in Week 10 against the Cincinnati Bengals, Baltimore Ravens quarterback Lamar Jackson earned another AFC Offensive Player of the Week award. It’s his second consecutive week winning the honor and his third of the season through just nine games.

Jackson completed 15-of-17 passes for 223 yards, three touchdowns and no interceptions, marking his second perfect 158.3 passer rating this season. Jackson also dazzled on the ground, adding 65 rushing yards and a touchdown on seven attempts, including a highlight-reel 47-yard scamper.

Jackson continues to pile up AFC Player of the Week awards, which has him in the mix for the NFL’s MVP award this season. With Baltimore sitting atop the AFC North standings and holding the No. 2 overall seed in the AFC playoff picture at 7-2, Jackson has helped put the Ravens at the top of the league. If he continues to play like he did in Week 10 against the Bengals, this won’t be Jackson’s last award this season, though he might have to miss the NFL Honors ceremony to prepare for Super Bowl LIV.

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