Rayshawn Jenkins named AFC Defensive Player of the Week

It was an easy choice for AFC Defensive Player of the Week.

Jacksonville Jaguars safety Rayshawn Jenkins is the AFC Defensive Player of the Week after a career day against the Dallas Cowboys in Week 15.

Jenkins, 28, was a pretty easy choice for the NFL after he became the first player ever to record at least 18 tackles and two interceptions in a game. His second pick Sunday was returned 52 yards for a game-winning overtime touchdown.

Jaguars quarterback Trevor Lawrence has earned AFC Offensive Player of the Week honors twice this season, but Jenkins is the first player on the team to win on the other side of the ball. Last year, Josh Allen was named AFC Defensive Player of the Week after recording a sack, interception, and a fumble recovery against the Buffalo Bills.

Jenkins began his career with the Los Angeles Chargers and joined the Jaguars in 2021 as a free agent. After Sunday, he has three interceptions on the season with 11 pass deflections and 95 total tackles.