A.J. Brown has been dominant over the past month, and the Eagles star was rewarded for his latest effort, earning NFC Offensive Player of the Week honors.
Brown earned the award after catching ten passes for 137 yards and a touchdown in Sunday night’s 31-17 win over the Miami Dolphins at Lincoln Financial Field.
11's just doing his thing đź’Ş@1kalwaysopen_ | #FlyEaglesFly pic.twitter.com/tTxuq4hoCS
— Philadelphia Eagles (@Eagles) October 25, 2023
After a slow start to the season, Brown has 52 receptions, 809 yards, and three touchdowns, ranking fourth in the league in receptions, second in receiving yards, tied for second in catches of 20- and 40-plus yards, tied for second in receptions for first downs, and fifth in yards after the reception.
This is the first Offensive Player of the Week honor of Brown’s car
Brown is the third Eagle to receive the weekly conference award, and it’s the fourth time this season the Eagles have been recognized by the NFC.
Running back D’Andre Swift was named the NFC Offensive Player of the Week after his Week 2 performance against Minnesota when he rushed for a career-high 175 yards and one touchdown on 28 carries in the win over the Vikings.
Placekicker Jake Elliott has twice been named the NFC Special Teams Player of the Week – after his Week 1 performance when he kicked four field goals, including successful kicks from 48, 51, and 56 yards, and then after booting a 54-yard field goal in Week 4 to secure a 34-31 overtime win over Washington at Lincoln Financial Field.
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