Texans DE J.J. Watt has 3rd best odds to win NFL Comeback Player of the Year

Odds-makers like Houston Texans defensive end J.J. Watt’s chances of winning the 2020 NFL Comeback Player of the Year.

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2020 may be the year that Houston Texans defensive end J.J. Watt wins another league-wide award.

According to BetMGM, the three-time NFL Defensive Player of the Year has the third-best odds to take home the NFL Comeback Player of the Year with 6 to 1 odds. Only Pittsburgh Steelers quarterback Ben Roethlisberger and Tampa Bay Buccaneers tight end Rob Gronkowski have better odds at 4 to 1 each.

In 2018, Watt seemed to be in the running for his fourth NFL Defensive Player of the Year award when Los Angeles Rams defensive tackle Aaron Donald blew the doors off the whole competition with his 20.5 sacks, 25 tackles for loss, 41 quarterback hits, and four forced fumbles. Donald was a force that no one was going to stop, not even Watt in the DPOY voting.

The next award Watt would have been eligible for, comeback player of the year, was also dominated by another player. Like so many times in the AFC South, Indianapolis Colts quarterback Andrew Luck was snatching victory away Watt, as his 39 touchdowns, second in the NFL, helped the Colts signal caller take home the comeback award.

Watt missed eight games in 2019 with a torn pectoral muscle sustained in Week 8. The Texans put the defensive end on injured reserve, but he returned in time for the AFC wild-card against the Buffalo Bills at NRG Stadium. Watt had a sack in the 22-19 overtime win.

The last NFL award Watt secured was the 2017 Walter Payton Man of the Year honor for his efforts in raising money for relief efforts in Houston and south Texas following the devastation from Hurricane Harvey. Though it was a momentous and emotional to win that award at that time, certainly the former 2011 first-round pick would love to collect another on-field award.


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