Another key member of the Los Angeles Rams defense has found a new home. According to NFL Network, the New York Giants and A’Shawn Robinson have agreed to terms on a one-year deal. It has a max value of $8 million, which is a good payday for the veteran defensive lineman.
Robinson signed with the Rams back in 2020 and spent the last three years with them, helping them win a Super Bowl in his second season. Robinson missed time due to a medical condition in 2020 and suffered a torn meniscus last November, causing him to miss the rest of the season.
In three seasons, he played 35 games with the Rams and started 24 of those, making 121 tackles with two sacks and four tackles for a loss.
The #Giants have agreed to terms with #Rams FA DT A’Shawn Robinson, continuing to beef up their defensive front right before the Draft, sources tell me and @MikeGarafolo. He gets a 1-year deal worth up to $8M max value with the opportunity to find a home with NYG. pic.twitter.com/K53jVNi77Y
— Ian Rapoport (@RapSheet) April 24, 2023
He joins Greg Gaines as the second defensive lineman to leave Los Angeles this offseason; Gaines signed a one-year deal with the Buccaneers. The Rams are suddenly thin up front, lacking talent around Aaron Donald on the interior.
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